Chemistry 11

Chemistry Level 2

How many moles of electron weighs one kilogram?

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6.022 × 1 0 54 9.108 \frac{6.022\times10^{54}}{9.108 } 1 0 31 9.108 \frac{10^{31}}{9.108 } 1 0 8 9.108 × 6.023 \frac{10^{8}}{9.108 \times 6.023} 6.022 × 1 0 23 6.022\times10^{23}

Akhil Bansal by Akhil Bansal , 22, India

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1 solution

Akhil Bansal
Jul 21, 2015

Mass of an electron = 9.108 × 1 0 − 31 9.108\times10^{-31} kg
Therefore, 9.108 × 1 0 − 31 9.108\times10^{-31} kg = 1 electron.
1 kg = 1 9.108 × 1 0 − 31 \frac{1}{9.108\times10^{-31}} electrons= 1 0 31 9.108 × 6.023 × 1 0 23 \frac{10^{31}}{9.108\times6.023\times10^{23}}

= 1 0 8 9.108 × 6.023 \frac{10^{8}}{9.108 \times 6.023} mole of electrons.

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