Molecular Orbital Theory!

Chemistry Level 2

$\displaystyle \sigma1s^{2} ~~\sigma^{\ast}1s^{2} ~\sigma2s^{2} ~~\sigma^{\ast}2s^{2} ~~\sigma2{p}_{z}^{2} ~~ \left| \begin{matrix} { \pi 2p }_{ x }^{ 2 } \\ { \pi 2p }_{ y }^{ 2 } \end{matrix} \right| ~~ \left| \begin{matrix} { \pi^{\ast} 2p }_{ x }^{ 1 } \\ { \pi^{\ast} 2p }_{ y }^{ 1 } \end{matrix} \right| ~~\sigma^{\ast}2p_{z}^{0}$

Predict the molecule/compound/ion from the above MOT configuration.

\ce{CN^{-}}

\ce{O_{2}^{2-}}

\ce{CO}

\ce{NO^{-}}

1 solution

Sahil Silare
Sep 17, 2016

$As\ we\ look\ from\ electronic\ configuration,$ $Atomic\ number>7.\ So,\ sigma\ electrons\ will\ be\ firstly\ filled.$ $So,\ by\ counting\ the\ electrons\ in\ the\ configuration\ we\ get\ 16\ electrons,$ $CN^-has\ 14\ electrons\ \left(Both\ species\ has\ electron\ less\ than\ or\ equal\ to\ 7\right)$ $CO\ has\ 14\ electrons\ \left(Electronic\ confiuration\ has\ 16\ electrons.\ Hence\ this\ doesn't\ satisfy\right)$ $O_2^{-2}has\ 18\ electrons\left(Electronic\ confiuration\ has\ 16\ electrons.\ Hence\ this\ doesn't\ satisfy\right)$ $NO^-has\ 16\ electrons\ \left(Electronic\ confiuration\ has\ 16\ electrons.\ This\ satisfies\ the\ configuration\right)$

Molecular Orbital Theory!

1 solution

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