Moment of Inertia

Classical Mechanics Level 1

A mass of 1 kg 1\text{ kg} is placed at ( 1 m , 2 m , 0 ) . (1\text{ m}, 2\text{ m}, 0). Another mass of 2 kg 2\text{ kg} is placed at ( 3 m , 4 m , 0 ) . (3\text{ m}, 4\text{ m}, 0).

Find the moment of inertia of the system about the z z -axis.

65 kg m 2 65\text{ kg m}^2 55 kg m 2 55\text{ kg m}^2 60 kg m 2 60\text{ kg m}^2 50 kg m 2 50\text{ kg m}^2

Soumya Shrivastva by Soumya Shrivastva , 20, India

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2 solutions

Rahul Awasthi
Jan 21, 2018

When calculating MOI about Z axis, simply find the polar distances of points with respect to the Z-axis i.e. radius of two points. Now simply use formula I=mr^2 So (√1^2+2^2)=√5 (√3^2+4^2)=5 For particle 1, m=1kg. so I=1×(√5)^2=5 For particle 2, m=2kg. So I=2×5^2=50 Total= 55kg= I.

11 Helpful 1 Interesting 1 Brilliant 2 Confused
Sub Zero
Mar 5, 2018

This Problem As I Think Can Be Solved By Adding their Individual MOI About the Z axis Use perpendicular axis theorem about individual masses and just add them..Cheers 🌟Can I Have A Smile Now😊

2 Helpful 0 Interesting 0 Brilliant 0 Confused

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