Moment of inertia of disc

Classical Mechanics Level 2

A uniform disc of radius $R$ and mass $M$ is spun to a angular velocity of $\omega_{0}$ and then it is placed on a horizontal surface. Find the moment of inertia of the disc about the rotating axis.

I = \frac{MR^2}{2}

I = MR^2

I = \frac{MR^2}{4}

I = \frac{R^2}{2M}

1 solution

Umang Vasani
Jun 9, 2014

Its very simple. See the link below to get useful info about the moment of inertia of disc and other objects. Moment of Inertia

Moment of inertia of disc

1 solution

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