Moment of Intertia

If the moment of inertia of a solid sphere with uniform mass density and total mass m m and radius R R which is rotating around its tangent axis can be written as a b m R 2 , \frac{a}{b} mR^2,

where a a and b b are coprime positive integers , find a + b a+b .


The answer is 12.

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1 solution

Sargam Yadav
Jul 30, 2016

the moment of inertia of a solid sphere about its central axis is 2/5(MR^2)... BY APPLYING PARALLEL AXIS THEOREM moment of inertia about tangential axis = 2/5 MR^2 +MR^2=7/5MR^2 ....SO, a=7 and b=5 .......a+b=7+5=12

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