Momentum 01

A cricket ball of mass 150g moving with a speed of 126km/h hits at the middle of the bat, held firmly at its position by the batsman. The ball moves straight back to the bowler after hitting the bat. Assuming that collision between ball and bat is completely elastic and the two remain in contact for 0.001s, what is the magnitude of the average force that the batsman had to apply in order to hold the bat firmly in its place?

1.05 x 10^4 N 21 N 2.1 x 10^4 N 10.5 N

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Raj Rajput
Jan 21, 2016

I nearly understand the solution except m(v-u) = 5/18 * x... ,what is 5/18 is come from,thanks

丁大喵 by丁丁猫 - 2 years, 8 months ago

Log in to reply

I have mentioned there , 1 km/hr = 5/18 m/s ( Conversion Factor !! )

RAJ RAJPUT - 1 year, 10 months ago

5/18 is just you convert km/h into m/s

Songtao Chen - 1 year, 3 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...