Money!

Suppose there are $x$ men who are to divide $N$ Rs. Then, the amount of money given to each man when divided equally is $N/x$ . From the problem description:

$\begin{cases} \frac{N}{x-3} = \frac{N}{x} + 150 \\ \frac{N}{x+6} = \frac{N}{x} - 120 \end{cases}$

Solving each for $N$ by factoring out $N$ and simplifying:

$\begin{cases} N = 50x(x-3) \\ N = 20x(x+6) \end{cases}$

Substituting for $N$ and solving for $x$ gives the number of men $x = 9$ .

Write a solution. Let no of people=x n total money=y ATQ (x-3)(y+150)=xy (x+6)(y-120)=xy From these eqns x=9