Monkeys typing on Typewriters

Lorcan the monkey sits on a typewriter and types 6 letters randomly. The probability that he types out ``lorcan'' on the typewriter can be expressed as a b \frac ab where a a and b b are co-prime positive integers. Find the remainder when a + b a+b is divided by 1000?

Details and Assumptions

The typewriter consists of 26 buttons labelled a a to z z , and no other buttons


The answer is 777.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Yan Yau Cheng
Apr 14, 2014

There are 26 possibilities for each letter, and there are 6 letters so there are (26^6=308915776) different combinations that Lorcan the Monkey could have typed. Out of these combinations 1 of them is "lorcan" therefore the probability that he types out "lorcan" on the typewriter is 1 308915776 \frac{1}{308915776} So a = 1 a=1 and b = 308915776 b=308915776 . Therefore a + b = 308915777 a+b = 308915777 . The remainder when a + b a+b is divided by 1000 is 777, so the answer is 777 \boxed{777}

1/26^6. So answer is 1+26^6%1000=777

Avinash Singh - 7 years, 1 month ago

i was correct.....but i attempted with log...and went wrong

Max B - 7 years, 1 month ago
Ángela Flores
Apr 20, 2014

Each letter of "lorcan" has the probabilty of 1/26. Then the total probabilty is given by 1/26^6. Then we need to find x, when x=1+26^6(mod 1000), of this, x=777

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...