Tongue Rolling

Biology Level 2

Given that the ability to roll a tongue is a dominant trait, if a heterozygous tongue-roller marries a non-tongue roller , what is the probability that their child is a non-tongue roller ?


Punnett squares are used to estimate the probability of inheriting a certain gene by crossing the alleles from both parents. A capitalized letter is used to show a dominant trait while a non-capitalized letter shows a recessive trait. Here's an example:

25% 100% 50% 0% 75%

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1 solution

Sravanth C.
Feb 16, 2016

As Steven is heterozygous for the particular trait, his genes must be of the form Xx \text{Xx} . And as Natalie must be having homozygous recessive condition as she can't roll her tongue hence it should be xx \text{xx} . Now let's draw a punnet square:

X x x Xx xx x Xx xx \begin{array}{|l|c|r|} \hline & \text X & \text x \\ \hline \text x & \text{Xx} & \text{xx} \\ \hline \text x & \text{Xx} & \text{xx}\\ \hline \end{array}

From the table, we can easily deduce that the probability of their child being a non-roller is 50 % 50\%

Natalie is homozygous recessive so hers will be xx not Xx

Kushagra Sahni - 5 years, 4 months ago

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Sorry for that typo thanks!

Sravanth C. - 5 years, 4 months ago

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