There is a condition for the following function to be monotonic:
The condition is:
Find the minimum value of .
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The monotonic function is the function that has its derivative:
f ′ ( x ) < 0 for all real x values
or
f ′ ( x ) > 0 for all real x values
In other words, f ′ ( x ) = 0 must not have real roots
f ′ ( x ) = 3 x 2 + 2 a x + 3
For ( 3 x 2 + 2 a x + 3 = 0 ) not to have any real roots, this condition must be met:
4 a 2 − 3 6 < 0
a 2 − 9 < 0
∣ a ∣ < 3
So the solution is:
k = 3