A circle of radius 1 is inscribed in a square which is in turn inscribed in a bigger circle which is in turn inscribed in a bigger square. Find the area of the larger square.
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The diameter of the smallest circle, is equal to the side of the square, insciribing the circle and the diagonal of that square is equal to the diameter of the bigger circle which is again equal to the side of the biggest square. So ans: [2(2)^1/2]^1/2 = 8