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The vapour pressure of a certain liquid is given by the equation:
logP = 3.54595 - + 1.40655logT
( P- Vapour Pressure in mm of Hg & T- Temperature in Kelvin )
Now find out the molar latent heat of vapourisation as a function of temperature and find its value at a temperature of 80K (in calories).
(Take the value of R to be 8.314 J mol K and 1 calorie to be 4.2 joule)
The answer is 1652.853.
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1 solution
Here I was revising the chapter and then I thought why not use the whole (almost) of Liquid Solution Relations to solve this and here it is