More on Comparing Areas

Geometry Level 2

Semicircles were constructed on the sides of a right triangle as shown in the figure . Let G G and R R represents the green area and the red area respectively. Compare the red and the green areas?

G > 2 R G>2R G < R G<R G > R G>R G = 2 R G=2R G = R G=R

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1 solution

Chew-Seong Cheong
Nov 13, 2019

Let the side lengths of the right triangle be a a , b b , and c c , where c c is the hypotenuse and the blue area be B B . Then the blue area is given by:

B = π c 2 4 R R = π c 2 4 B \begin{aligned} B & = \frac {\pi c^2}4 - R \\ \implies R & = \frac {\pi c^2}4 - B \end{aligned}

and the green area:

G = π a 2 4 + π a 2 4 B Since a 2 + b 2 = c 2 = π c 2 4 B \begin{aligned} G & = \frac {\pi a^2}4 + \frac {\pi a^2}4 - B & \small \blue{\text{Since }a^2+b^2=c^2} \\ & = \frac {\pi c^2}4 - B \end{aligned}

Therefore, G = R \boxed{G=R} .

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