∫ π / 2 ∞ x 8 + 1 0 x 5 + 2 5 x 2 x 4 cos x + 5 x cos x − 4 x 3 sin x − 5 sin x d x
If the above integral can be represented in the form
a ( 2 π ) b + c ( 2 π ) d − 1
where b > d , and a , b , c , d are positive integers, find a + b + c + d .
Details and assumptions:
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Problem Loading...
Note Loading...
Set Loading...
Notice that the integrand can be rewritten as
( x 4 + 5 x ) 2 ( cos x ) ( x 4 + 5 x ) − ( 4 x 3 + 5 ) ( sin x )
Doesn't that look like the quotient rule? It IS the quotient rule.
Then we have
x 4 + 5 x sin x ∣ ∣ ∣ ∣ π / 2 ∞
which gives us
∞ A number between − 1 and 1 − ( 2 π ) 4 + 5 ( 2 π ) 1 = − ( 2 π ) 4 + 5 ( 2 π ) 1
and that gives 1 + 4 + 5 + 1 = 1 1