More variables than equations

Algebra Level pending

Let r = s 2 r =\dfrac{s}{2} , s = 7 t s=7t , t = 2 u t=2u , u = 3 v u=3v , v = 4 w v= 4w , w = 10 z w=10z and z 0 z\neq 0 .

Find the value of r + s + t + u + v + w z 3 \dfrac{r+s+t+u+v+w}{z^{3}} .

2903 2931 2930 2913

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1 solution

Hana Wehbi
Jun 4, 2016

Since all the other variables are build upon z z , so use the picking numbers strategy; pick a small number for z z and find the values for the rest of the variables. For instance, let z = 1 z=1 then w = 10 , v = 40 , u = 120 , t = 240 , s = 1680 , and r = 840 w=10, v=40, u= 120, t= 240, s= 1680, \text{and} r= 840 \implies

r + s + t + u + v + w z 3 \Large\frac{r+s+t+u+v+w}{z^{3}} = 2930 2930 by substitution.

Yes , that's it. Did the exact same way.

Aniruddha Bagchi - 5 years ago

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Thanks. I found this way is the quickest way to solve it.

Hana Wehbi - 5 years ago

Question, Hana......shouldn't the denominator equal z instead of z^3 in order to achieve 2930 as the correct result? Otherwise, z has to equal unity.

tom engelsman - 4 years, 3 months ago

@Tom Engelsman , the question has the denominator as z 3 z^3 but when we solved it since we have more variables than equations, plugging a certain value for z z was helpful.

Hana Wehbi - 4 years, 3 months ago

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