There are many locks and 9 people. At least 5 people are needed to open all the locks. If the number of locks is small as possible, how many keys does each person have?
Details and Assumptions
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Each 4 cannot open all the locks. So for every four people that we choose there is one key missing. All the other people out of this group should have this key.
So ( 4 9 ) ∗ 5 keys are needed. Since the number of locks are minimum under the above condition each 5 can open all the doors and each 4 can't.
So each person must have ( 4 9 ) ∗ 5 / 9 = 70 keys.