Morley's Test Scores

(93+88+95+x)/4=91 91 4=93+88+95+x x=(91 4)-88-93-95 x=88

Let the unknown score be y. We know that average of a number of quantities is given by the sum of all the quantities divided by the total number of quantities. Here, the average to be obtained is 91. Hence, according to the question,
( 93 + 88 + 95 + y ) / 4(Total no. of Quantities) = 91
( 276 + y ) / 4 = 91
276 + y = 91 x 4
y = 364 - 276
y = 88

• Let x be the minimum score Morley needs to attain in order get an A.
• The condition for having an A is that Morley must have an average score of 91 in four tests.
• Given that the first three scores are 93, 88 and 95, Morley must have a minimum score (x) of

\frac {(93+88+95+x)}{4} = 91 \Rightarrow x = (91 \times 4) - (93+88+95) = 88.

To average 91, his four test scores must total 4*91=364. His three scores total 276. This means his 4th test score must be 364-276=88.

(Morley's Previous Test Scores + Future Test Score) / 4 = 91 If "Future Test Score" equals "x" then.... (93+88+95+x) / 4 = 91 --> (276+x) / 4 = 91 --> Multiply 4 to either side ... 276+x = 91(4) --> 276+x = 364 --> Subtracting 276 from both sides... x = 364-276 --> x = 88 --> Therefore, Morley should get a minimum of 88 on the next test to get an A.

91*4=364, 93+88+95=276, 364-276=88, Solution is 88

4*91-93-88-95

(93+88+95+x)/4=91

276+x=362

x=88

----------------------- do good have good ------------------------------ mean =93+88+95+m/4 let m= minimum no that need to score in ordre to get a no ? mean=91 then 91=93+88+95+m/4 91*4=276+m 364-276=m m=88 answer

sum of first three test = 93+88+95 = 276 sum of all four test = 91*4 = 364 So he should get 364-276 = 88 marks

(93+88+95+X)/4=91 276+X=364 X=364-276 X=88

(93+88+95+x)/4 = 91 then 276+x=364 then x= 88

first step: to calculate the gap of the first three test scores and targeted average score: (93-91)+(88-91)+(95-91)=3, which means the last test min. score can be 3 lower than the targeted average 91 last step: to calculate the last test min.score=91-3=88

Se trimestralmente são efetuados quatro testes (sendo que cada teste é avaliado de 0 a 100), e que a a média minima para ter um resultado A é de 91,temos: minimo da soma das provas= 91*4= 364. Então temos (sabendo as três primeiras notas de Morley )= 93+88+95+x=364; 276+x=364;x=364-276;X=88 =D

93+88+95+x/4=91

276+x=364

x=88

93 is 2 surpassed the average, 95 is 4, 88 is -3. That leaves him with a positive 3 on the average, that means he can get a -3 on the last one to get average scoore.

91*4 times = 364

364 - 93 - 88 - 95 = 88

to find the total marks he needs to score use 91 times 4, which is 364. using this number, minus the scores for his first three test scores, resulting in 88.

the average of the four tests should be 91, so i took average of four numbers with unknown as X and put it equal to 91. from there i found the value of X.