Mosaic Squares

Geometry Level 1

ABCD is a square of side length 4.

What is the area of the figure?

16 + 8 π 16 + 8 \pi 8 + 8 π 8 + 8 \pi 16 + 16 π 16 + 16 \pi 8 + 16 π 8 + 16 \pi

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1 solution

Michael Huang
Nov 15, 2016

Clearly, the area of the square is A square = 4 2 = 16 A_{\text{square}} = 4^2 = 16 Observe that half of each square side resembles the radius of the circle, which is 2 2 . Since there are 4 4 semicircles, the area of all semicircles is A circles = 4 π 2 ( 2 ) 2 = 8 π A_{\text{circles}} = 4 \cdot \dfrac{\pi}{2} (2)^2 = 8\pi Thus, A total = A circles + A square = 8 π + 16 \begin{array}{rl} A_{\text{total}} &= A_{\text{circles}} + A_{\text{square}}\\ &= 8\pi + 16 \end{array}

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