An exceptionally fast (and strong) mosquito pushes on the back of a moving airplane.
The mosquito supplies a force of and does work on the plane at a rate of .
At what mach number (multiple of the speed of sound) is the airplane moving?
Assume:
- The speed of sound is
-
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P = F ⋅ v = F v as the mosquito supplies the force in the same direction as the plane’s velocity. Then, P = 7 4 6 W = 1 N ⋅ v ⟹ v = 7 4 6 m / s . Therefore the mach number of the plane is 3 3 0 7 4 6 = 2 . 2 0 6 .