A 5-Digit Number[Positive Integer] with Sum of Its digits to be equal to 2 is formed.The probability that it contains ONE is....
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Only 5 nos can be formed.... 10001..... 10010.... 10100..... 11000.... and 20000..... Clearly Four out of Five numbers contain 1...HENCE, p(E) is 4/5....i.e....( 0.8 )....Hence The Solution....