Motion Graphs

Classical Mechanics Level 2

The position-time graphs for two particles $A$ and $B$ are straight lines inclined at angles of $30$ degree and $60$ degree in respect with the time axis.

If the ratio of their velocities is $X/Y$ , what is $Y-X$ ?

For more problems see my sets Motion and Gravity .

The answer is 2.

1 solution

Sravanth C.
Mar 15, 2015

We know that slope $(=\tan \theta)$ of displacement-time graph shows the velocity.mTherfore,

$\begin{aligned}\text{Velocity of particle A}&=\tan 30^\circ=\dfrac{1}{\sqrt{3}}\\ \text{Velocity of particle B}&= \tan 60^\circ=\sqrt{3} \end{aligned}$

Thus the ratio is: $\dfrac{1/\sqrt 3}{\sqrt 3} = 1/3$

The required value is $3 - 1 = 2$

Motion Graphs

For more problems see my sets Motion and Gravity .

The answer is 2.

1 solution

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