motion in 1D

Assume that initial velocity $v_i=0$ , obviously initial distance $d_i=0$ , and knowing that basically $\displaystyle d = \int v~dt=\iint a~dtdt$ , we have: $d = \iint a~dtdt=\int at+v_i~dt = \dfrac{1}{2}at^2+v_it+d_i$ Because $v_i$ and $d_i$ are zero, we have $d = \dfrac{1}{2}at^2$

In problem, we are given $a=3.2~m/s^2$ and $t=32.8s$ . Plug in these values and solve it, we got $d = 1721.344\approx\boxed{1720}$

Use the expression s=1/2(a*t^2) . Answer obtained is 1721.344 . Round up the answer to 1720 (standard answer)