Motion in a Straight Line 1

Classical Mechanics Level 2

A ball is released from the top of tower of height h h metres. It takes T T seconds to reach the ground.What is the position of ball in T 3 \dfrac T3 seconds?

2 h 3 \frac{2h}{3} 8 h 9 \frac{8h}{9} h 3 \frac{h}{3} h 2 \frac{h}{2}

Gts 07 by GTS 07 , 21, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Anita Gupta
May 21, 2019

Ball is dropped, so initial velocity of the ball is 0 Using equation no.2 ut=0 Time =T s =h g=g So ,h=1g/2 Tsq. ....... 1 In T/3 sec S=1g/2 (T/3)sq. .......2 We have h=1g/2*Tsq. Substitute the value

0 Helpful 0 Interesting 0 Brilliant 1 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...