Motion in an electric field (reposted)

Electricity and Magnetism Level 3

An electron at rest is subjected to an electric field of Intensity $5 \frac{N}{C}$ for $2$ seconds.

Find the distance traveled by the electron during this $2$ second interval.

If the answer is of the form $a.bcd \times 10^e$ , where $a>0$ , then input answer as $a+b+c+d+e$

The answer is 33.

1 solution

Rohit Ner
Jun 2, 2015

For a point charge in an electric field, the force is given by $\large F=qE\\\large\Rightarrow ma=qE\\\large a=\frac{qE}{m}\\\large s=\frac{1}{2}at^{2}\\\large\Rightarrow s=\frac{Eqt^{2}}{2m}$ Substituting the values neccesary in the given equation, we obtain the distance travelled as $\huge\color{#3D99F6}{\boxed{1.758\times {10}^{12}}}$

@Vaibhav Prasad , I feel that you should mention about the direction of the electric field in the question as well, although some people might not need to that. Thanks:)

A Former Brilliant Member - 6 years ago

Motion in an electric field (reposted)

The answer is 33.

1 solution

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