Move beyond mains

Classical Mechanics Level 5

A triatomic non-linear ideal gas is taken through a cyclic process A B C ABC as shown. The process A B AB is an adiabatic process. Find percentage efficiency of the cycle to the nearest integer.

Note: Vibrational degrees of freedom are neglected.


The answer is 22.

A Former Brilliant Member by A Former Brilliant Member

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Rajdeep Brahma
May 1, 2017

Let the gas expand n times in the process.(T1 temp at B,T0 temp at C).gamma=y= C p C v \frac{Cp}{Cv}
Q2(Heat released)=CpXT1X(1- 1 n \frac{1}{n} )
Since adiabatic,T0=T1Xn^(y-1).
So Q1=CvX(n^y-1)X T 1 n \frac{T1}{n}
E=1- Q 2 Q 1 \frac{Q2}{Q1} =1- y ( n − 1 ) n y − 1 \frac{y(n-1)}{n^y-1}
Calculate with values,to get n= 27 8 \frac{27}{8} and y= 4 3 \frac{4}{3}
EX100=22(approx.)=ANSWER


4 Helpful 0 Interesting 0 Brilliant 0 Confused

You should improve latex

Md Zuhair - 3 years, 4 months ago

Happy I did the same

Prabhat Rao - 3 years ago
Topper Forever
Feb 12, 2018

Yo i am the best, if u have brain rajdeep singh dhingra beat me in inpho

0 Helpful 0 Interesting 0 Brilliant 1 Confused

Wow!? What a lajhand(not legend) you are! You challenge, But you afraid to give your real name. Claps!

Md Zuhair - 3 years, 2 months ago

Log in to reply

what did he mean btw @Md Zuhair ??....I still didn't get lol...

rajdeep brahma - 3 years ago

Log in to reply

Rajdeep Singh dhingra is quite a genius boy in JEE 19 batch.... He is IJSO Gold medalist and uses brilliant. Moreover he got AIR 3 in KVPY 2017 SA. That's why this guy challenges Him. 😂😂

Md Zuhair - 3 years ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...