You are trying to move a brick on the floor by meters at a constant speed. You push the brick with a constant magnitude of force, using both arms which form an angle of with the floor. What is the magnitude of the work (in J) you put on the brick if the coefficient of kinetic friction between the floor and brick is
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Draw the free body diagram. equating the force equations along y axis- N=mg+Fsin32 frictional force=0.2(Fsin32+mg) now equate force wquation along x axis- Fcos32=frictional force so, on solving the equations we get F=87.146 N now work done=Fcos32 x distance moved =739J