let x=0.12345678...................998999 where the digits are obtained by writing the integers 1 through 999 in order. The 1983 rd digit to the right of the decimal point is Q . Find Q
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There are 9 digits in the nine one-digit numbers. Then, there are 180 digits in the first ninety two-digit numbers. That adds up to 189 digits that have passed so far. We have 1794 digits left. Sine the rest of the numbers are three digits, we must divide 1794 by 3 to find out how many numbers have passed until we get to the number that has the 1983rd digit. 1794/3 = 598. 100 + 598 -1 = 697. Since 598 is an integer, the 1983rd digit refers to the last digit of 697, or 7.