Mr. Robot?

Chemistry Level 2

Morphine (an addictive drug) has the molecular formula C X 17 H X 19 N O X 3 \ce{C17H19NO3} .

What is the mass of one molecule of morphine in grams?

(Atomic weights: C = 12.01 , H = 1.008 , N = 14.01 , O = 16.00 \ce{C}=12.01, \ \ce{H}=1.008, \ \ce{N}=14.01, \ \ce{O}=16.00 )

2.24 × 1 0 22 2.24 \times 10^{-22} 3.58 × 1 0 21 3.58 \times 10^{-21} 3.85 × 1 0 22 3.85 \times 10^{-22} 4.74 × 1 0 22 4.74\times 10^{-22}

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

One mole of morphine is = 17 × 12.01 + 19 × 1.008 + 14.01 + 3 × 16.00 = 285.332 g = 17 \times 12.01 + 19 \times 1.008 + 14.01 + 3 \times 16.00 = 285.332 \text{ g} .

The number molecules in 1 mole of morphine is Avagadro constant N A = 6.0221408 × 1 0 23 N_A = 6.0221408 \times 10^{23}

Therefore, the mass of a molecule of morphine = 285.332 6.0221408 × 1 0 23 = 4.74 × 1 0 22 g = \dfrac {285.332}{6.0221408 \times 10^{23}} = \boxed{4.74 \times 10^{-22}} \text{ g}

@achal jain , I have edited your problem wording. You should mention "in grams" in your problem. You can key in chemical formula by putting "\ce{ }" around the chemical equation, as in

You can see the LaTex keystrokes by placing your mouse cursor on top of formula as I have done. You can also click the top-right pull-down menu button and select Toggle LaTex.

Chew-Seong Cheong - 4 years, 9 months ago

I have to study my middle classes again, forgot Avagadro!

Viki Zeta - 4 years, 9 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...