For integers a and b , let ⊗ be the binary operation a ⊗ b = ( a × a ) − ( b × b ) . What is the value of 4 ⊗ 3 ?
This problem is posed by Mukul G .
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a = 4 b = 3
(a . a) - (b . b) = (4 . 4) - (3 . 3) = 16 - 9 = 7
a=4 and b=3 so(4x4)- (3x3)=16-9=7
given: a@b = (a a) - (b b) now, a=4, b=3 => 4@3= (4 4) - (3 3) = 16 - 9 = 7 (answer)
a⊗b=(a×a)−(b×b). So, 4⊗3 = (4×4)-(3×3) = 16-9 = 7
4⊗3 = (4 x 4) - (3 x 3)
4⊗3 = 16 - 9
4⊗3 = 7
we see that: a⊗b=(axa)-(bxb) so: if a=4 and b=3 => we have: (4x4)-(3x3)=7
( 4 * 4 ) - ( 3 * 3 ) = 7
I multiplied a by a and b by b then subtracted the solutions
since, our binary operation define as : a⊗b=(a×a)−(b×b) then , plug in a & b by 4 & 3 we get : 4⊗3 = (4x4) - (3x3) = 16 - 9 = 7
You have (4 x 4) - (3 x 3). You follow the order of operations and get 16 - 9. Your answer is 7.
4⊗3 = (4x4) - (3x3) = 16-9 = 7
let a = 4, b = 3 , u'll get 4^2 - 3^2 = 16 - 9 = 7
putting value of a=4 and b=3, we get (4 x 4) - (3 x 3) = 16 - 9 = 7
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a⊗b=(a×a)−(b×b)
So, in 4⊗3, a = 4 & b = 3
Now, 4⊗3 becomes