Find the number of terms in the expansion of ( 1 + x + x 2 + x 3 + . . . + x 3 3 ) 3
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The answer is of the form a 0 x 0 + a 1 x 1 + a 2 x 2 + a 3 x 3 + . . . + a 9 9 x 9 9 @Pi Han Goh Thank you for the correction.
No problem. But I feel that your answer is inadequate. You need to prove that coefficients of x 4 , x 5 , … , x 9 8 are non-zero.
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These coefficients are surely greater than zero.
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you have to find the grade and then plus 1, in this case 33+33 +33 = 99, then 99 + 1= 100 , 100 is the number of terms