Multinomials? You Sure?

Find the number of terms in the expansion of ( 1 + x + x 2 + x 3 + . . . + x 33 ) 3 \large {(1+x+{x}^2+{x}^3+. . .+{x}^{33})}^{3}


The answer is 100.

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2 solutions

Oscar Rojas
Jul 13, 2015

you have to find the grade and then plus 1, in this case 33+33 +33 = 99, then 99 + 1= 100 , 100 is the number of terms

Rohit Ner
Jun 30, 2015

The answer is of the form a 0 x 0 + a 1 x 1 + a 2 x 2 + a 3 x 3 + . . . + a 99 x 99 {a}_{0}{x}^{0}+{a}_{1}{x}^{1}+{a}_{2}{x}^{2}+{a}_{3}{x}^{3}+. . .+{a}_{99}{x}^{99} @Pi Han Goh Thank you for the correction.

No problem. But I feel that your answer is inadequate. You need to prove that coefficients of x 4 , x 5 , , x 98 x^4, x^5,\ldots, x^{98} are non-zero.

Pi Han Goh - 5 years, 11 months ago

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These coefficients are surely greater than zero.

Бранко Грбић - 5 years, 11 months ago

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