Inside a smooth circular tube of radius 5 m, a small ball A moves at speed 10 m/s and strikes another ball B with double the mass located at a diametrically opposite point, as shown in the figure. If the coefficient of restitution is 0.5 and the time when the second collision occurs is , find .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
From conservation of linear momentum (vertical direction at point of impact), m u = m u ′ + 2 m v ′ . From definiton of coefficient of restitution, we get u ′ = v ′ − 2 u , and subtituting into first equation, we have v ′ = 2 u and u ′ = 0 .
Therefore, the second collision will occur at the same point with the first collision, hence ball B will take the full circle before second collision occur. Then, T = v ′ 2 π R = u 4 π R = 2 π s .