Multiple of 3?

Is it true that the difference between any integer and its cube is always either 0 or a multiple of 3?

Yes No

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1 solution

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Dec 3, 2018

n 3 n = n ( n 1 ) ( n + 1 ) n^3-n=n(n-1)(n+1) . One of ( n 1 ) , n , ( n + 1 ) (n-1),n,(n+1) will be a multiple of 3, so the answer is yes.

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