The angle between two mirrors is θ . If the incident ray that is parallel to mirror 1 is reflected 5 times in the setup, and becomes parallel to mirror 1 again. What is the measure (in degrees) of θ ?
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Total deviation is 180+ theta how can it identify
@Madhuri: I've drawn a diagram which traces the exact path of the ray and explains the solution much better but I do not know how to upload the diagram. If you would write to me at ajitathle@gmail.com, I can forward it to you.
For Incident and Reflection angles to be equal, the condition can only be met for five reflection if there is a symmetry. And that means after third reflation the ray would trance back the same path. That means second reflection on m-2 must be at 90 degrees. If you draw the ray diagram you would see that the other two angles are Alpha/2 and Alpha = 90. Hence Alpha/2 = 30 .
thus.. there will be no two different parallel rays... the given pic is not realistic.
thita=pi/n+1 (where n is no. of refections) here n=5 so thita = 180/5+1=30.
Please correct the typo. n + 1 π = 5 + 1 1 8 0 = 3 0 .
What is this formula about can u elaborate ?
Here is a really nice way of thinking of the reflections.
From here it is obvious that θ = 1 8 0 / 6 = 3 0 ∘
An explanation I found elsewhere:
https://socratic.org/questions/two-plane-mirrors-are-included-at-an-angle-theta-as-shown-in-the-figure-light-ra
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Total Deviation = 360 - 5(θ) which in this case =180 + θ or 6θ=180° or θ=30°