Multiples

Find the sum of the two smallest positive integers that is disivisible by 2, 3 and 4.


The answer is 36.

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2 solutions

Jesse Nieminen
Sep 19, 2016

lcm ( 2 , 3 , 4 ) = 12 \text{lcm}\left(2,3,4\right) = 12 , and thus 12 12 is the smallest such positive integer, and the next one must be 24 24 because it's the next one divisible by 12 12 .

Hence, the answer is 12 + 24 = 36 12+24=\boxed{36} .

Sahil Silare
Sep 18, 2016

A s b y o b s e r v a t i o n , 12 i s t h e s m a l l e s t n u m b e r d i v i s i b l e b y 2 , 3 a n d 4 a n d n e x t n u m b e r i s 24. S o , 24 + 12 = 36. As\ by\ observation,\ 12\ is\ the\ smallest\ number\ divisible\ by\ 2,3\ and\ 4\ and\ next\ number\ is\ 24.\ So,\ 24+12=36.\

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