Multiplibonacci #4

Algebra Level pending

Which of the following is equivalent to ${ _{ x }{ M }_{ n } }$ ?

Note: ${ F }_{ n }$ is equivalent to the $n$ th number in the Fibonacci Sequence.

This problem is part of the Multiplibonacci set.

{ ({ F }_{ n }) }^{ x+1 }

{ x }^{ ({ F }_{ n-1 }) }

{ n }^{ { (F }_{ x+1 }) }

{ ({ F }_{ x }) }^{ n-1 }

{ ({ F }_{ n }) }^{ x-1 }

{ ({ F }_{ x }) }^{ n+1 }

{ x }^{ ({ F }_{ n+1 }) }

{ n }^{ { (F }_{ x-1 }) }

1 solution

Louis Ullman
May 18, 2018

From the solution to Multiplibonacci #2 , we know that the $n$ th Multiplibonacci number's power is always going to be the $n-1$ st Fibonacci number.

This means that ${ _{ x }{ M }_{ n } }={ x }^{ ({ F }_{ n-1 }) }$ .