Multiplicative Dilemma Part 2

Calculus Level 3

n = 0 1 + ϕ ( n ) 1 μ ( n ) 1 + τ ( n ) \sum_{n=0}^{\infty}\frac{1+\phi (n)}{1-\frac{\mu (n)}{1+\tau (n)}} What happens with above sum?


Try Part 1 .
Insufficient Information Recall Euler Diverges Converges

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1 solution

If n = 1 1 + ϕ ( n ) 1 μ ( n ) 1 + τ ( n ) \sum_{n=1}^{\infty} \frac{ 1 + \phi(n)}{1 - \frac{ \mu(n)}{1 + \tau(n)}} converged then one necessary condition(not a sufficient condition) would be lim n 1 + ϕ ( n ) 1 μ ( n ) 1 + τ ( n ) = 0 \lim_{n\to \infty} \frac{ 1 + \phi(n)}{1 - \frac{ \mu(n)}{1 + \tau(n)}} = 0 but if you take p a prime number 1 + ϕ ( p ) 1 μ ( p ) 1 + τ ( p ) \frac{ 1 + \phi(p)}{1 - \frac{ \mu(p)}{1 + \tau(p)}} does not tend to 0 when p p \to \infty and p a prime number. Furthemore, all terms in this series are positive, therefore this series diverges.

Exactly ! .....

A Former Brilliant Member - 5 years, 3 months ago

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