Let be integers such that for all integers and there exist integers and for which and .
Find the absolute value of .
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Taking m = 1 and n = 0 gives integers x 1 and y 1 with a x 1 + b y 1 = 1 and c x 1 + d y 1 = 0 . Similarly, taking m = 0 and n = 1 gives x 2 and y 2 with a x 2 + b y 2 = 0 and c x 2 + d y 2 = 1 .
Then we compute
( a d − b c ) ( x 1 y 2 − x 2 y 1 ) = ( a x 1 + b y 1 ) ( c x 2 + d y 2 ) − ( c x 1 + d y 1 ) ( a x 2 + b y 2 ) = 1 ⋅ 1 − 0 ⋅ 0 = 1 .
Since these are integers, we must have a d − b c = ± 1 .