Two small stones
of masses
and
respectively, are projected simultaneously at
. The stone
is projected horizontally with speed
from the top of a tower that is
meters high and the stone
is projected from the ground at a distance
meters from the foot of the tower with speed
at an angle of
with the horizontal as shown in the figure. At time
after projection, they collide in air and at that moment their velocities are mutually perpendicular. Then find
Note: give the sum of the numerical values of .
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write the velocity in vector form Va=v(-i)+gt(-j)-------1 Vb=90cos37 (i)+90sin37-gt(j)-------2 at 6s they are perpendicular =-->Va.Vb=0(dot product)----3 putting t=6 and combining 1,2,3- Va=5 x=(90cos37+5) 6=462 y(sitting in frame of b)=90sin37*6=324 -->x+y+Va=791