A number is less than 100 and its tens digit is 2 more that its units digit. If the number with the digit reversed is subtracted from the original number, the remainder is 3 times the sum of the digits. find the number
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Forget that. I just guessed. Lololol
Hey this problem is wrongly titled, anyways solved it.
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nope its correctly titled, personally i am 21 years old as of the moment, the title is age after 21 more years . 21 + 21 = 42, get it?
aren't x is 4?
Cant 84 be the answer ?
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it can't be.you are missing on the condition that the ten's digit is two more than the one's digit
It could be but it also can't be since he is 21. Cause 21+21 =42 and I figured out that he is 21 from 42-21=21. If you said 84, 84-21= 63 . And that guy does not look 63.
awesome question !!! ......got 42 :)
Solved it!!!!! Nice question upload some more please
nice question!\
I think... ques was fine.... but not wid unique soln..... 00,21,42,63,84 all these no are satisfying d ques... den how to guess in 3 trials.....
Answer to everything in the universe.
Nonsense stuff from the Hitchhikers guide to the galaxy
x = tens digit y= units digit
x =2 +y original no. = 10x + y reversed no. = 10 y + x sum of digits = x +y
formulate: (10x + y) - ( 10y + x ) = 3 ( x + y) y = 2, x = 4
then 42. love it
Suppose a number yx. According to question, y=x+2. Writing the expanded form, (Example 28=2 10 + 8) Original number= (x+2) 10+x Reversed number=x 10+(x+2) Subtract both, you'll get=18. The question says, 18(the subtraction)=3 [(x+2)+x] Solve this, you'll get, x=2. Age was, yx, hence, age becomes 42.
Let the number be 1 0 x + y
it's given that 1 0 x + y − ( 1 0 y + x ) = 3 ( x + y )
since x = y + 2 then
1 0 ( y + 2 ) + y − 1 0 y − ( y + 2 ) = 3 ( 2 y + 2 )
6 y + 6 = 1 8
y = 2 and so x = 4
thus the number is 4 2
Actually you only need to read the title and see his face
System of Equations
( a + b ) ( ( a ∗ 1 0 + b ) − ( b ∗ 1 0 + a ) ) = 3
a = b + 2
Substitute b+2 for a: ( ( b + 2 ) + b ) ( ( ( b + 2 ) ∗ 1 0 + b ) − ( b ∗ 1 0 + ( b + 2 ) ) ) = 3
Solve for b: b = 2
Substitute 2 for b: a = 2 + 2
Solve for a: a = 4
Answer: 4 2
Notes: a*10+b describes the components of the desired number, with a in the tens place and b in the ones place
((a 10+b) – (b 10 + a))/(a+b)=3 describes "If the number with the digit[s] reversed is subtracted from the original number, [then ]the remainder is 3 times the sum of the digits ."
a-2=b (rewritten as) a=b+2 describes "A number is less than 100 and its tens digit is 2 more tha[n] its units digit."
Formatting this was hard, tedious, and still now how I would have liked.
<p>This question seemed absurd in the way it was worded... In any case here is a simple solution that I used to solve it. I listed all the possible numbers that can be produced from 0-9 that satisfy the tens digit being 2 more than the units: 01234567 units, note that any higher and the tens digit would be zero. The possibilities are therefore 20,31,42,53,64,75,86,97. He said in the title that the number is 21 years + his current age. You can see that he is 20 from his profile and 42 is the closest number that satisfies this condition. Thus 42. </p>
The number will be of the form (n+2, n) [Example: 53 = (5, 3)] in the ten's and unit's place. Replacing the values of n from 1 to 7 (as the number should be less than hundred), the only possible set of such numbers is {31, 42, 53, 64, 75, 86, 97}. By inspection, 42 satisfies the given condition [42-24 = 18 = 3*(2+4)]... Hence, the number is 42.
Let units digit be x then tens digit is x+2, the original number value is x+10 (x+2) = 11x+20, the reversed number value is (x+2)+10x = 11x+2, Subtraction operation will equal 18, sum of digits is x+(x+2) = 2x+2, Solving 3 (2x+2) = 18 gives x = 2, so the number is 42
let the tenht of the original number is x ,and the unit is y ,so,the first number equal 10x+y,and the second reversed number equals 10+x then you have two equations :
substract the #1 from the #2 you get the value of x ,then substract in any equation you get the value of x the number equals 10x+y i hope its the suitable way to solve :)
Original Number (N1): 10x+y. So, the reversed Number (N2): 10y+x. N1-N2 = 9(x-y); Now, it is given that 9(x-y)=3(x+y) => x=2y; Also, given that x=y+2 => y+2=2y =>y=2 and x=4; Hence N1 is 10(4)+2 = 42
Let the number be " ab " with its unit digit ans ' b ' and tens digit as ' a '...so the number = 10 a + b ...And since tens digit i.e ' a ' is 2 more than units digit i.e ' b '.This implies that a=b+2 ... And reverse number is " ba " i.e. 10 b + a ...And since the difference between the original and the reverse number is 3 times the sum of digits of the number....Therefore (10a+b)-(10b+a) = 3(a+b) Solving which we get.. a = 2b ---------- Equation 1 ; and since a = b+2 -------------------------- Equation 2 ; Solving 1 and 2 we get a=4 and b=2 ; i.e the number is number = 10*a+b or just ab = 42 ......................... Answer
Any number less than 100 is of the form 10x + y where x is the tens digit and y is the ones digit . The number becomes10x+(x-2) = 11x-2 . Now from the question x comes out to be 4 .
Let the ten's digit of the number be x and unit's digit be y. Then,
The original number = 10x + y............(1) ( for eg : 58 can be written as 10 (5) + 8 )
From condition 1) x = 2 + y
or, x - y = 2..........................(2)
From condition 2) (10y + x) - (10x + y) = 3(x+y)
10y + x -10x - y = 3x + 3y
9y - 9x -(3x + 3y) = 3x + 3y - (3x + 3y)
=> 6y - 12x = 0 ...........................(3)
solving equations (2) and (3) we get
x = 4 and y= 2
From (1)
then, the number is 10 (4) + 2 = 42
Don't understand why there is a picture of this guy on this problem, may be effect of puberty.
I am the boy on the photo, you did not understand me. he is the boy after 21 years
Numbers are 31, 42, 53, 64, 75, 86, 97. Their reversals are 13, 24, 35, 46, 57, 68, 79. In all cases, difference is 18. Therefore, 18 = 3(4+2) = 3(2+4). Hence, the number is 42.
Let unit's digit be x and ten's digit is y. Then original number =10y+x Now after the digits are reversed The new expression is =10x+y
So according to the question the difference is equal to thrice the sum of the digits. (10y+x) - (10x+y) =3(x+y) So x=2, And according to the question ten's digit is two more than unit's digit, so y=x+2=4. So the number is 42.
since the difference b/w one's and tens digit is 2..
so the difference b/w the required no. and its reversed no. will always be 18 (as it is 2 digit no.)..
according to question, equating 18 = 3((x+2) + x) gives x=2 (ones place) & x+2 = 4 (tens place)
so the solution is 42
:)
(x+2)+x-(10x+x+2)=(x+2+x)3
=> x=42
we are given with that the tens digit is 2 more than the units place and when reversed and subtracted the remainder is 3 times the number. so you can either use tricks or trial method by just guessing the no. like in 42 the sun is 6 and after reversing the remainder is 42-24=18 and the remainder is 3 times the sun of digits.
Let unit digit be 2 and tens digit be 2 + 2 Subtraction _ 42 - 24 = 18 which is 3 times the sum of 2 + 2+2 =6
10 (x+2)+x - 10x + x + 2 = 18 = 3 (2x+2) Hence x=2 So the number is 42.
I thought that the tens digit is 2 times more than units digit... so I list all the value 21,42,63,84... minus the reversed and I got the value is 3 times the sum of the both digit... all possible is correct. Hehe
-noob-
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Let units digit be x then tens digit is x+2 , the original number value is x+10 (x+2) = 11x+20 , the reversed number value is (x+2)+10x = 11x+2 , Subtraction operation will equal 18 , sum of digits is x+(x+2) = 2x+2 , Solving 3 (2x+2) = 18 gives x = 2 , so the number is 42