Find the value of to the nearest whole number (i.e. ).
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First, start by finding a common denominator: x 6 x 6 ⋅ x 5 5 x − 1 + 2 x − 5 − x 5 x 5 ⋅ x 6 5 + x − 4 This becomes: x 1 1 5 x 5 + 2 x 1 − x 1 1 5 x 5 + x 1 You then simplify: x 1 1 5 x 5 + 2 x 1 − 5 x 5 − x 1 = x 1 1 x Get rid of like terms: x 1 0 1 You are left with: y = ζ ( 1 0 ) = i = 1 ∑ ∞ x 1 0 1 ≈ 1 . 0 0 0 9 9 Rounding to the nearest whole leaves us with 1.