My first problem
Classical Mechanics
Level
3
A particle is projected from a point A with a velocity of 10 m/s at angle of to the horizontal .At a certain point B it moves at right angle to its initial direction .Find the velocity at this point in m/s.
The answer is 17.32.
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1 solution
the horizontal speed is constant and equal to 8.66 m/s. When it is 90 degree from its initial direction it is 60 degree below horizontal. Thus horizontal velocity=8.66=vcos60, solve it and the required velocity v is 17.32.