a 2 a 1 + a 3 a 2 + a 4 a 3 + … + a n a n − 1 + a 1 a n
Given a 1 , a 2 , a 3 , … , a n > 0 for n > 2 . If the expression above has a minimum value of p n for p is a positive integer, then find the value of p + 1 .
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Simple standard approach.
nice job bro, thank you.
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By AM-GM, we have n a 2 a 1 + a 3 a 2 + . . . + a 1 a n ≥ n a 2 a 1 × a 3 a 2 × . . . × a 1 a n = 1 . Thus, the minimum value of the sum is n .
Equality can be achieved by setting a 1 = a 2 = . . . = a n , so p = 1 , and the final answer is 2 .