My little brother's challenge for you!

Let's write every natural number n > 1 n>1 in form of a table as below:

A \text{A} B \text{B} C \text{C} D \text{D} E \text{E}
2 3 4 5
9 8 7 6
10 11 12 13
17 16 15 14
18 19 20 21

Based on the table, in what column would the number 2015 appear?

B \text{B} A \text{A} E \text{E} D \text{D} C \text{C}

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1 solution

Leah Smith
Sep 18, 2015

There are quite a few solutions to this problem, but here is my brother's:

We can easily see that the numbers on column a, c, e are even number . Let n be any natural numbers, we can figure out that:

○ Every number in column a represents 8n + 2 .

○ Every number in column c represents 4n .

○ Every number in column e represents 8n + 6 .

2014 = 8*251 + 6, so it would be written in column e .

2016 = 4*504, so it would be written in column c .

Hence, 2015 would be written in column d

To put it differently: The multiples of 8, like 8 , 16 , . . , 2016 , . . 8,16,..,2016,.. are in column C, and their predecessors, like 7 , 15 , . . 2015 , . . 7,15,..2015,.. , are in column D.

Otto Bretscher - 5 years, 8 months ago

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