My name is equation................X Y equation... got it......

Algebra Level 3

find the sum of all the integral solutions of x and y.


The answer is 0.

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2 solutions

Check this out x 3 y 3 = 127 x^3-y^3=127

= > x y = 1..................1 =>x-y=1..................1

now considering 2nd equation,

x y [ x y ] = 42 xy[x-y]=42

= > x y = 42.............2 =>xy=42.............2

Now using 1st equation it is found that the integral solutions are

x = 7 , 6 , y = 6 , 7 x=7,-6 , y=6,-7

so their sum is 0 \boxed{0}

You must mention that 127 is prime

Jayakumar Krishnan - 7 years ago
Moshiur Mission
Apr 3, 2014

(x-y)^3 = 127-3*42 so x-y = 1 or x = 1+y taking integral x^2/2 = y^2/2+y implies x = y =0

Why are you taking integrals? The condition only holds at a set of points, and not necessarily over the entire line / region.

Note that x = 7 , y = 6 x = 7, y = 6 and x = 6 , y = 7 x=-6, y=-7 are the only solutions, which is why they sum to 0.

Calvin Lin Staff - 7 years, 1 month ago

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After getting x-y =1 , how did you get the roots?

aditya chandratre - 7 years ago

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