My problems #13(Easiest problem of the set)

Algebra Level 1

Let

t n = { n 2 if n Even n 2 1 if n Odd t_n=\begin{cases} n^2&\mbox{if}\ n\in \text{ Even} \\ n^2-1 &\mbox{if}\ n\in \text{Odd} \end{cases}

Find

t 19 \huge t_{19}


The answer is 360.

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2 solutions

As 19 Odd 19 \in \text{Odd} so t 19 = 1 9 2 1 = 361 1 = 360 t_{19}=19^2-1=361-1=\boxed{360}

this should be level 0 problem

Vyom Jain - 6 years, 1 month ago
Joe Mansley
Oct 17, 2015

19 is odd. (19^2)-1=(19+1)(19-1)=20*18=360

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