My problems #9

Number of ways men and women can be seated alternately $=$ $\dfrac{4!\times 4!\times 2!}{8}$ $= 144$

And number of ways by which all women gets seated adjacent to her husband $=$ $\dfrac{4!\times 2!\times 2}{8}$ $= 12$

hence the number of ways in which $4$ maried couples can be seated round a table such that men and women are alternate and not all women adjacent to her husband $= 144 - 12$ $= 132$