My Quadratics

Algebra Level 2

If ( a 2 1 ) x 2 + ( a 1 ) x + a 2 4 a + 3 = 0 (a^2-1)x^{2}+(a-1)x+a^{2}-4a+3=0 satisfies strictly more than two values of x then the value of 'a' is


The answer is 1.

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1 solution

Ravi Dwivedi
Jul 24, 2015

Since the given equation is quadratic and have more than two roots. Then it must be an identity i.e. the function should be 0 0 for all real values of x x

This is possible when coeff of x 2 x^2 = coeff of x x = constant term

This yields a = 1 \large a=1

Moderator note:

Simple standard approach.

The question could have been made slightly more interesting by posing it as a quartic in a a instead.

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