A Huge Sum of Interior Angles

To solve this problem, you need to know the following formula:

Sum of the angles in an $n$ -gon = $(n - 2)\times 180^\circ$ .

n is the number of sides. So just plug in the numbers and solve

$\begin{aligned} 2340^\circ& = (n - 2)\times 180^\circ\\ 2340^\circ& = 180^\circ n - 360^\circ\\ 2340^\circ + 360^\circ & = 180^\circ n - 360° + 360^\circ\\ 2700° &= 180^\circ n\\ \frac{2700^\circ}{180^\circ} &= \frac{180^\circ n}{180^\circ }\;\; \text{(Dividing both sides by} 180^{\circ})\\ 15& = n \end{aligned}$

Therefore,the $n$ -gon has $\boxed{15}$ sides