n n to the n t h n^{th}

Let k = n = 1 10100 n n ( m o d 101 ) k=\displaystyle\sum_{n=1}^{10100}{n^n} \pmod{101} where 0 k 100 0\le k\le 100

k + 50 k+50 people sit in a circle. They are numbered 1 1 through k + 50 k+50 . Starting with person 2 2 , every other person leaves. So 2 , 4 , 6 2,4,6 etc leave, and it loops back to the beginning when you get to k + 50 k+50 because it's a circle. What is the number on the last person to remain after that process?


The answer is 45.

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