Name Probability

A letter is known to have come either from 'TATA NAGAR' or from 'CALCUTTA' . On the envelope, just two consecutive letters TA are visible. What is the probability that the letter came from 'TATA NAGAR' ? The answer will be in the form of p q \frac{p}{q} , where p p and q q are coprime positive integers, find p + q p+q .


The answer is 18.

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2 solutions

Let A be the event that the letter is from TATA NAGAR and B be the event that letter is from CALCUTTA .

Also, let E be the event that on the letter, two consecutive letters TA are visible.

P(A) = 1 2 \frac{1}{2} ; P(B) = 1 2 \frac{1}{2}

And P(E/A) = 2 8 \frac{2}{8} and P(E/B) = 1 7 \frac{1}{7}

[ If the letter is TATA NAGAR, we see that the events of two consecutive letters visible are { TA, AT, TA, AN, NA, AG, GA, AR }. So P(E/A) = 2 8 \frac{2}{8} and same in case of CALCUTTA, so P(E/B) = 1 7 \frac{1}{7} ]

Therefore, P(A/E) = P ( A ) . P ( E / A ) P ( A ) . P ( E / A ) + P ( B ) . P ( E / B ) \frac{P(A).P(E/A)}{P(A).P(E/A) + P(B).P(E/B)}

= ( 1 / 2 ) ( 2 / 8 ) [ ( 1 / 2 ) ( 2 / 8 ) ] + [ ( 1 / 2 ) ( 1 / 7 ) ] \frac{ (1/2) * (2/8) }{[(1/2) * (2/8)] + [(1/2) * (1/7)]}

= ( 1 / 8 ) ( 1 / 8 ) + ( 1 / 14 ) \frac{(1/8)}{(1/8) + (1/14)}

= ( 1 / 8 ) ( 11 / 56 ) \frac{(1/8)}{(11/56)}

= 7 11 \frac{7}{11}

p = 7 , q = 11; p+q = 11 + 7 = 18

Could you explain the logic behind that formula?

Mehul Arora - 5 years, 4 months ago

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Its Baye's Theorem, proposed by a person known as Baye. You will study about that in class 12.

Samara Simha Reddy - 5 years, 4 months ago

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Lol, you sound quite like my teachers :P

Mehul Arora - 5 years, 4 months ago

Cool problem but the fact that there was a space between the A and N in TATA NAGAR made it seem a little ambiguous.

Tristan Goodman - 1 year, 4 months ago
Raj Sancheti
Feb 12, 2016

Obj approach ... selecting 1 out of 17 :1/17

Could you explain the basis

Swapnil Vatsal - 3 years, 9 months ago

Didnt get it...

Arunava Das - 3 years, 5 months ago

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